(2+3x)^(2)+(2-3x)^(2)=26

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Solution for (2+3x)^(2)+(2-3x)^(2)=26 equation: 



(2+3x)^(2)+(2-3x)^(2)=26

We move all terms to the left:

(2+3x)^(2)+(2-3x)^(2)-(26)=0

We add all the numbers together, and all the variables

(3x+2)^2+(-3x+2)^2-26=0

We move all terms containing x to the left, all other terms to the right

(3x+2)^2+(-3x+2)^2=26

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